0=2(x^2+2x-600)

Solution for 0=2(x^2+2x-600) equation:

0=2(x^2+2x-600)

We move all terms to the left:

0-(2(x^2+2x-600))=0

We add all the numbers together, and all the variables

-(2(x^2+2x-600))=0


We calculate terms in parentheses: -(2(x^2+2x-600)), so:

2(x^2+2x-600)

We multiply parentheses

2x^2+4x-1200

Back to the equation:

-(2x^2+4x-1200)


We get rid of parentheses

-2x^2-4x+1200=0

a = -2; b = -4; c = +1200;
Δ = b2-4ac
Δ = -42-4·(-2)·1200
Δ = 9616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9616}=\sqrt{16*601}=\sqrt{16}*\sqrt{601}=4\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{601}}{2*-2}=\frac{4-4\sqrt{601}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{601}}{2*-2}=\frac{4+4\sqrt{601}}{-4}
$